Physics question?
An artillery shell is fired with an initial velocity of 300 m/s at 50.5° above the horizontal. To clear an avalanche, it explodes on a mountainside 49.0 s after firing. What are the x and y components of the shell where it explodes, relative to its firing point?
x=9350.35
y=
I don t know what y=
Answers
Born Yesterday
This can be as simple as y = ax² + bx + c y = -4.9(49)² + sin(50.5)×300×(49) ≈ -422 feet below launch altitude. Distance is cos(50.5)×300×49 = 9350
Some Body
x = x₀ + v₀ t + ½ at² x = 0 + (300 cos 50.5) (49.0) + ½ (0) (49.0)² x = y = y₀ + v₀ t + ½ gt² y = 0 + (300 sin 50.5) (49.0) + ½ (-9.81) (49.0)² y =
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