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Fuel aboard a rocket has a density of 2700 kg/m3 and is ejected with a speed of 4410 m/s. If the engine is to provide a thrust of 1.21 × 106 N, what volume of fuel must be
burned per second?
Answer in units of m3/s.
Answers
Whome
F = (dm/dt)v F = ρ(dV/dt)v dV/dt = F/ρv dV/dt = 1.21 × 10^6 / (2700)(4410) dV/dt = 0.102 m³/s that's 102 liters per second If this is helpful to you, please vote a Best Answer.
billrussell42
1.21 × 106 N ?? that is about 130 N ?
Andrew
m3 is m^3 And the thrust is 1.21 x 10^6
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