What is the derivative of ln(x^3+2)-sinx?

Como

- f ` (x) = (3x²)/(x³ + 2) - cos x

khalil

[ln(u)]' = u' / u [3x² / (x³ + 2)] - cos(x)

rotchm

What is the derivative of ln(x) or of ln(u)? Then apply the chain rule.

Engr. Ronald

y = ln(x^3 + 2) - sin(x) ..................1 dy/dx =-------------- d/dx 3x^2 - cos(x) ............x^3 + 2 .........3x^2 =------------------ - cos(x) answer// ....x^3 + 2

MyRank

ln (x³ + 2) - sinx Differentiation with respect ‘x’ 1/(x³+2) . d/dx (x³+2) - cosx 1/(x³+2) . (3x²) - cosx 3x²/x³+2 - cosx.

Philip

f = ln(u) -sin x. df/dx = d/du[ln(u)]*du/dx -d/dx[sinx],where u = x^3 +2. Then df/dx = (1/u)(3x^2) -cosx = 3x^2/(x^3 + 2) - cosx