How many moles of carbon dioxide (CO2) will occupy 5.5 L at 5.0°C and 0.74 atm?

electron1

Let’s use the following equation. P * V = n * R * T R = 22.4 ÷ 273 T = 5 + 273 = 278˚K 0.74 * 5.5 = n * (22.4 ÷ 273) * 298 6,675.2 * n = 1,111.11 n = 1,111.11 ÷ 6,675.2 The number of moles is approximately 0.166. I hope this is helpful for you.

david

PV = nRT n = [0.74 X 5.5] / [0.0821 X 278] <<< use a calculator