How long would it take for 1.50 mol of water at 100.0 ∘C to be converted completely into steam?

if heat were added at a constant rate of 20.0 J/s ?
Answers

Roger the Mole

(1.50 mol H2O) x (40660 J/mol) / (20.0 J/s) = 3049.5 s = 50.8 minutes

david

1.50 X 18 X 2260 / 20.0 = 3051 seconds