Bauxite, the principle ore used in the production of aluminum cans, has a molecular formula of Al2O3•2H2O.?
a. what is the molar mass of bauxine
b. what is the mass of aluminum in 0.58 moles of bauxite
c.how many atoms of aluminum are in 0.58 mole of bauxite
d.what is the mass of 2.1 * 10^24 formula unit of bauxite?
Answers
billrussell42: Al₂O₃•2H₂O Al: 26.981 g/mol H: 1.008 g/mol O
Al₂O₃•2H₂O Al: 26.981 g/mol H: 1.008 g/mol O: 15.999 g/mol rounding: Al₂O₃•2H₂O : 2•27+5•16+4•1 - 54+80+4 = 138 g/mol 0.58 moles x 138 g/mol = 80 g of Bauxite 0.58 moles x 54 g/mol = 31 g of Al 6.022e23 molecules/mole Avogadro constant 0.58 moles x 6.022e23 molecules/mole = 3.49e23 molecules Bauxite 2 atoms of Al per molecule, so 6.99e23 molecules Al 2.1e24 molecules of bauxite / 6.022e23 molecules/mole = 3.49 mol 3.49 mol x 138 g/mol = 481 g
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