Find 2 points of a line if given gradient, length, and one point.?

supastremph

Given the slope, you know that a change in y over a change in x is -3/2. From the point (3,-1) we then know (y-(-1))/(x - 3) = -3/2. By Pythagoras we want (y+1)^2 + (x -3)^2 = 5^2 to make sure the distance is 5. We know that (y+1) = -3/2(x-3), so 9/4(x-3)^2 + (x - 3)^2 = 25 13/4(x-3)^2 = 25 (x - 3)^2 = 100/13 x = 3 +- (100/13)^(.5) So x = 0.23 or 5.77 (We know there are two points the same distance away from a point along a line) Substitute these values of x in the first equation to find their corresponding y values on the line.