Need help with shifting all values to the left of an array and place a 0 in the last location each time it is called.?

Create a new Java program called LeftShift. Create an array size 10 that contains 1’s and 0’s only. (Any combination.) Create a method called shiftValues that passes an array. It should shift all values to the left and place a 0 in the last location each time it is called. Call your shiftValues method a three times to show shift. Paste code here once completed. NOTE: To earn the extra credit, program must show use of the pass by reference concept, which means you should only have one array throughout the entire program. import java.util.*; public class LeftShift{ static Random r=new Random(); public static final int dice=2; public static final int size=10; public static final int count=5; public static void main(String[] args){ int[] a=new int[size]; for(int i=0;i<size;i++){ int seq=r.nextInt(dice); a[i]=seq; } System.out.println("Sequence: "+Arrays.toString(a)); for(int i=0;i<count;i++){ shiftValues(a); } } public static void shiftValues(int[] a){ for(int i=0;i<a.length-1;i++){ a[i]=a[i+1]; a[a.length-1]=0; } System.out.println("Sequence: "+Arrays.toString(a)); } }